4m^2-1=325

Solution for 4m^2-1=325 equation:

4m^2-1=325

We move all terms to the left:

4m^2-1-(325)=0

We add all the numbers together, and all the variables

4m^2-326=0

a = 4; b = 0; c = -326;
Δ = b2-4ac
Δ = 02-4·4·(-326)
Δ = 5216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5216}=\sqrt{16*326}=\sqrt{16}*\sqrt{326}=4\sqrt{326}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{326}}{2*4}=\frac{0-4\sqrt{326}}{8}
=-\frac{4\sqrt{326}}{8}
=-\frac{\sqrt{326}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{326}}{2*4}=\frac{0+4\sqrt{326}}{8}
=\frac{4\sqrt{326}}{8}
=\frac{\sqrt{326}}{2}
$